FOAK: Volume

You keep banging on about this. A litre is a unit of volume. One litre
of water has the same volume as one litre of air, in exactly the same
way that one pound of feathers has the same mass as one pound of lead.

If he was asking what _mass_ of water could be held within that cylinder,
you might have a point. But he didn't, and you're starting to get very
repetitive in an "I'm a smart arse and I know better" kind of way.

 

Try this calculation then
Consider a circle of radius a (the end of the tank) and imagine that
the liquid has reached height h, measured from the lowest point on the
circle. Note that 0 <= h <= 2a. The area A of the segment of the
circle covered by the liquid is:

A = pi*a^2/2 - a^2*arcsin(1-h/a) - (a-h)*sqrt(h(2a-h))

The volume of liquid is just A*L, where L is the length of the tank.

OK !!!


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Robbo
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..

 

First time I mentioned it. And the point is still being missed.

 

Depends if it's hollow, and how hollow it is, obviously.

 

Cane

No worries. One question, one answer. As you didn't ask
how to calculate this, I didn't bother typing out long equations,
and still getting them wrong as so many others here. ;-)

 

What a very IBM answer.

 

Cane says...

None if it has no bottom.

 

Hardly, the first question IBM might ask is whether there is anything
else in the cylinder before the water is added.

and then it'd be a question of whether that item floated...

and then...

<breathes out, and thinks of far away places>

 

Temperature and pressure?

 

I was thinking along the lines of totally correct but useless answers.

 

They're going to be bloody heavy - approx 992 pounds or almost 71 stone
each. I hope they're not planning on standing them on some cheap display
unit or on an unstrengthened floor.

Shame they'd be crap for keeping fish, or I'd ask you to make some for
me too - surface area is too small <sulk>

 

Ginge says...

IBM would insist that you use their hugely expensive dihydrogenoxide
rather than 'ordinary' water.

 

Weight could be cut substantially by putting a smaller cylinder inside, with
about a 1" gap all round, and only fill the space between the cylinders with
water. This will give you a cylindrical shell of water - if they're
planning to bubble air through, for instance - and a dry core for lighting
or display. In fact, you could run all sorts of interesting lighting
effects on the inner cylinder a la perspex dinosaurs.

 

mups says...

and then...

 

You don't understand - though Cane will have, having heard me expound
on this theory: all quantities are "some" and all foreign money is
"things".

 

That'll be the "Blaney code".

 

If you'd said ~460 litres you wouldn't be wrong, but 462 is a
wrong answer.

olsonm@debian:~$ echo '4*a(1) * (650/2)^2 * 1400 / 10^6'| bc -l
464.56301364959067513431

 

Do keep up at the back!

 

OY!

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FFS find the snipping wizard, will you? It is becoming tiresome
having to scroll through a screenful of quoted text to find your
single-line addition at the bottom.